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3 years ago

What is the equation of the line that is perpendicular to y = -2/3x + 4 and that passes through (–2,–2)?

Mathematics

1 answer:

Rama09 [41]3 years ago

6 0

Answer: y = 3/2x + 1

Step-by-step explanation: For a perpendicular line, take the reciprocal of "m" and reverse the sign.

- 2/3 becomes +3/2

Then substitute the y and x values of the given coordinate into the equation and solve for "b"

y = mx + b

-2 = 3/2(-2) + b

-2 = -3 + b

-2 +3 = b

+1 = b Substitute for b in y = (3/2)x + 1

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Find the rule of f(0)

kap26 [50]

Answer:

f(0)=4

Step-by-step explanation:

f(0)=4*9^0=4*1=4

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3 years ago

Your favorite football team has three games left to finish the season. the outcome of each game can be win, lose or tie. the num

Ann [662]

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4 0

3 years ago

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

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3 years ago

What is the surface area of this triangular pyramid?

noname [10]

I believe it would be 44.75 sq yards

5 0

2 years ago

One side of a square flower bed is 8 feet long. how many plants are needed if they are to be spaced 8 inches apart around the ou

Sloan [31]

The side is 8 feet = 8*12 inches = 96 inches

Plants are needed if they are to be spaced 8 inches apart around the outside of the bed

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Means total flower : 10 * 4 (each side) + 4(corner)

The total needed is 44 plants. : Answer

Hope that will help :)

4 0

3 years ago