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Anestetic [448]
3 years ago
8

Doing another onee! 50 points for answering thiss!

Chemistry
2 answers:
otez555 [7]3 years ago
7 0

Answer:

why u was giving free point and I think u have great day

MaRussiya [10]3 years ago
3 0

Answer:

are you increasing your followers

Explanation:

if yes then I will follow you

You might be interested in
How many moles of propane<br> react when 294 g of CO2 form?<br><br> C3H8 +502 → 3CO₂ + 4H₂O
tatiyna

2.23 moles of propane react when 294 g of CO₂ is formed .

<h3>What is moles ?</h3>

Moles is a unit which is equal to the molar mass of an element.

A reaction is given

C₃H₈ +50₂ → 3CO₂ + 4H₂O

Grams of CO₂ formed = 294 gm

In moles = 294 /44 = 6.68 moles.

Let x be the moles of C₃H₈ is x

Mole ratio of CO₂ to C₃H₈ = 3 : 1

so

6.68 /x = 3/1

x = 6.68 /3 = 2.23 moles

Therefore 2.23 moles of propane react when 294 g of CO₂ is formed .

To know more about Moles

brainly.com/question/26416088

#SPJ1

7 0
2 years ago
How many moles are in 25 grams of Li? How do you know?
Ipatiy [6.2K]

Answer:

3.6mol Li

Explanation:

To get the amount of moles from the mass we divide the mass by the molar mass.

25g ÷ 6.941g/mol = 3.6mol Li

8 0
3 years ago
Which of the following statements regarding energy changes during a reaction are true?. 1) If the heat of reaction, ΔH, is negat
sergejj [24]
2.<span>Two or more atoms must collide, with proper orientation, with energy greater than or equal to the activation energy for a reaction to occur</span>
4 0
3 years ago
Read 2 more answers
Which statements regarding the Henderson-Hasselbalch equation are true? If the pH of the solution is known as is the pKa for the
Sonbull [250]

Answer:

1, 2, and 3 are true.

Explanation:

The Henderson-Hasselbalch equation is:

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

  • If the pH of the solution is known as is the pKa for the acid, the ratio of conjugate base to acid can be determined. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If you know pH and pka:

10^(pH-pka) = \frac{[A^-]}{[HA]}

The ratio will be: 10^(pH-pka)

  • At pH = pKa for an acid, [conjugate base] = [acid] in solution. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

0 = log₁₀ \frac{[A^-]}{[HA]}

10^0 = \frac{[A^-]}{[HA]}

1 = \frac{[A^-]}{[HA]}

As ratio is 1,  [conjugate base] = [acid] in solution.

  • At pH >> pKa for an acid, the acid will be mostly ionized. <em>TRUE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If pH >> pKa,  10^(pH-pka) will be >> 1, that means that you have more [A⁻] than [HA]

  • At pH << pKa for an acid, the acid will be mostly ionized. <em>FALSE</em>

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

If pH << pKa,  10^(pH-pka) will be << 1, that means that you have more [HA] than [A⁻]

I hope it helps!

6 0
3 years ago
___________, is the process by which a nucleus of an unstable atom loses energy by
likoan [24]
<span>The answer to this would be radioactive decay. This is also known as "nuclear decay" or "radioactivity".</span>
4 0
3 years ago
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