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Ahat [919]
3 years ago
5

Solving for volume, what units do you use?

Chemistry
1 answer:
muminat3 years ago
3 0
The SI unit of volume is the cubic meter (m3)
You might be interested in
2.5 million atoms of a particular element have a mass of 8.33 x 10-16 grams. what is this element
jeyben [28]
Find the mass of one atom by:

8.33 x 10^{-16} / 2.5 x 10^{6}  = 3.32 x 10^{-22} g

Convert it into amu.
1 g = 6.022 x 10^{23} amu
so, 3.32 x 10^{-22}  x  6.022 x 10^{23}  =  200.6 amu

Now look at the periodic table and search for 200.6 amu element.
The element is Mercury (Hg)

5 0
3 years ago
A scientist notices that a lump of niobium is warm to the touch and wonders if nuclear reactions are taking place in the metal.
sertanlavr [38]

Answer is: Check for the presence of alpha, beta, and gamma particles.

1) Alpha particle is nucleus of a helium-4 atom, which is made of two protons and two neutrons.

Alpha decay is radioactive decay in which an atomic nucleus emits an alpha particle (helium nucleus) and transforms into an atom with an atomic number that is reduced by two and mass number that is reduced by four.

2) Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.

There are two types of beta decay: beta minus and beta plus.

3) During gamma emission the nucleus emits radiation without changing its composition.

5 0
4 years ago
Read 2 more answers
The speed of a water wave is 6.2 meters/sec. Its wave length is 0.50 meters. What is its frequency, cycles/see?
rusak2 [61]
The answer is 0.001515, I hope this helps!
6 0
3 years ago
Read 2 more answers
Which of the following nuclei would be the least stable
Brut [27]

Answer:

C. 1 proton 3 neutrons

Explanation:

A nucleus is more stable if the ratio of the neutrons to protons is between 1:1 and 1:1.5.

Thus the ratios of neutrons to protons for  the nuclei are as follows

A- 1:1

B- 1:1

C- 1:3

D- 1:2

Among these ratios, C is the greatest thus the nucleus is the least stable.

6 0
3 years ago
Read 2 more answers
A 100.0g sample of tin is heated to 100.0 oC (Celsius) and is placed in a coffee cup calorimeter containing 150. g of water at 2
Snowcat [4.5K]

Explanation:

It is known that specific heat of water is 4.184 J/g^{o}C and atomic mass of tin is 118.7 g/mol. For the given situation,

                 Q_{lost} = Q_{gained}

Let us assume that,

               m_{1} = mass of Sn

               m_{2} = mass of H_{2}O  

Therefore, heat energy expression for heat lost and gained is as follows.

           Q_{lost} = Q_{gained}

      m_{1}C_{1}(T_{2} - T_{1}) = m_{2}C_{2}(T_{1} - T_{2})

   100 g \times C_{1} \times (100^{o}C - 27.4^{o}C) = 150 g \times 4.184 /g^{o}C \times (27.4^{o}C - 25^{o}C)

           7260C_{1} = 150 \times 4.184 \times 2.4

                 C_{1} = \frac{1506.24}{7260}

                              = 0.207 J/g^{o}C

For, 118.7 g the specific heat of tin will be calculated as follows.

               C_{1} = 0.207 J/g^{o}C \times 118.7 g

                          = 24.5 J/mol^{o}C

Thus, we can conclude that specific heat of tin is 24.5 J/mol^{o}C.

3 0
3 years ago
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