Answer:
32 and 39
Step-by-step explanation:
The common difference d for the sequence is 7
1st term of the sequence a1 is 11.
4th (a4) and 5th (a5) term of the sequence are required
nth term of an arithmetic sequence an =a1+(n-1)d
a4=11+(4-1)7=32
a5=11+(5-1)7=39
What is the sum of 1.57 and 6.88?
Ok, so lets work this out together!
Sum means add.
6.88
+ 1.57
That would be:
= 8.45
Hope i helped!
Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper = sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining =
=
Using algebraic formula:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
Rational. Not whole or integer because its an exact measurement and not irrational because it CAN be expressed as a ratio (fraction, decimal measurement )
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Answer:
Step-by-step explanation:
Remember that it doesn't matter how many numbers are after the tenths place of a decimal point what matters is the tenths place itself. If you have a decimal that has dozens of numbers but it's tenth place is a 3 and then you have a decimal with 5 numbers in whole but it's tenths place is 4, the 4 is greater then the 3 simply because it's greater in tenths.
Hope this helps.