Answer:
we conclude that an inequality 'c ≥ 5' denotes this situation.
Step-by-step explanation:
Given
- A car dealer ship sells at least 5 minivans
When we talk about 'at least', it means we are talking about '≥' in terms of representing the 'at least' in inequality symbol.
For instance,
'm≥n' means 'm' is greater than or equal to 'n'.
It means 'm' is at least equal to 'n'.
Coming back to the question,
- Let 'c' represent the number of minivans sold each week.
As the car dealer ship sells at least 5 minivans. so the
inequality will be: c ≥ 5
Thus, we conclude that an inequality 'c ≥ 5' denotes this situation.
Answer:
1 7/12
Step-by-step explanation:
5/6+3/4=10/12+9/12 = 19/12 or 1 7/12
The 3-D shape would be created if the figure was rotated around the x-axis is a cone
<h3>What are 3-D shapes?</h3>
3-D shapes (short form of 3-Dimensional shapes) are shapes that have width, length and height
<h3>How to determine the 3-D shape?</h3>
The coordinates are given as:
(0, 0), (-3, -4) and (-3, 0)
When the above coordinates are plotted on a coordinate plane and the points are connected;
We can see that the points form a right-triangle
See attachment for the shape
As a general rule
Rotating a right-triangle across the x-axis would form a cone
Hence, the 3-D shape would be created if the figure was rotated around the x-axis is a cone
Read more about rotation at:
brainly.com/question/4289712
#SPJ1
Answer:
Originally there was 324 nuts in the bag.
Phillip took 108, Joy took 54, Brent took 81 and Preston took 10.
Step-by-step explanation:
Let's call the total amount of nuts N, and the number of nuts each child took by the initial of their name (Phillip will be P1 and Preston will be P2).
So we can write the following equations:
P1 = N/3
After removing N/3, the remaining nuts is (N - N/3):
J = (N - N/3)/4 = (2N/3)/4 = N/6
After removing N/6 from (N - N/3), the remaining nuts is (N - N/3 - N/6):
B = (N - N/3 - N/6)/2 = (N/2)/2 = N/4
P2 = 10
In the final there were 71 nuts remaining, so we have that:
N - N/3 - N/6 - N/4 - 10 = 71
N - N/3 - N/6 - N/4 = 81
N/4 = 81
N = 324 nuts
The amount of nuts took by each child is:
P1 = N/3 = 108 nuts
J = N/6 = 54 nuts
B = N/4 = 81 nuts
P2 = 10 nuts
