Answer:
Step-by-step explanation:
We have been given that a label wraps around soup can with a radius of 4.3 cm and a height of 6 cm. We are asked to find the lateral surface area of the label of the soup can in square centimeters.
We will use lateral surface area of cylinder to solve our given problem as:
, where,
r = Radius of cylinder,
h = height of cylinder.
Upon substituting our given values in above formula, we will get:
Therefore, the lateral surface area of the label of the soup is approximately 162.11 square cm.
Answer:
B. x-intercept: -6, y-intercept: -4
Step-by-step explanation:
2x + 3y = -12
x-intercept when y = 0
2x = - 12
x = -6
y-intercept when x = 0
3y = -12
y = -4
Answer:
DB = 6
Step-by-step explanation:
See the attached figure to the question.
Since O is the center of the given circle, so AB and CD are diameters of the circle.
Hence, AO = CO = OD = OB = radius of the circle = 6
In Δ OAC, we have AO = OC. Hence, ∠ A = ∠C = 60° {Given that ∠OAC = 60°}
So, ∠ AOC will automatically become 60°. {As the sum of all the angles of a triangle is 180°}
So, Δ AOC is equilateral triangle.
Now, ∠ AOC = ∠ BOD = 60° {Since, they are vertically opposite angles}
Now, in Δ BOD, we have DO = OB. Hence, ∠ D = ∠ B = 60° {As the sum of all the angles of a triangle is 180°}
So, Δ BOD is also an equilateral triangle.
So, DB = BO = DO = 6. (Answer)
7.89 is greater than 7.189, 6.03 is equal to 6.030, because that last zero doesn't really change anything it cancels itself out
Answer:
16
Step-by-step explanation:
