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Rom4ik [11]
3 years ago
9

Choose all that correctly solve for x.

Mathematics
1 answer:
Tamiku [17]3 years ago
8 0

Answer:

Options: A, B, and C correctly solve for x.

Step-by-step explanation:

A).

\frac{5}{2} x = \frac{15}{2}

Multiplying both sides by 2 gives;

5x = 15

x = 15 ÷ 5 = 3

∴ This option correctly solve for x.

B).

x + \frac{7}{2} = 7

x = 7 - \frac{7}{2} = \frac{14}{2} -\frac{7}{2} = \frac{7}{2}

∴ This option correctly solve for x.

C).

x + 3 = \frac{21}{5}

x = \frac{21}{5} - \frac{15}{5}  = \frac{6}{5}

But the option give x as 5/6 hence this option does not correctly solve for x.

D).

5x = 11/2

x = 11/2 ÷ 5 = 11/2 × 1/5 = 11/10

But the option gives x as 10/11 so it does not correctly solve for x.

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4000
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Answer:

$1000 ; 500 ; 1000 ; y = 500x + 1000

Step-by-step explanation:

From the graph, the initial deposit which started the savings account is $1000 ; this is the value on the y - intercept, the value in the account at time or period = 0.

The slope :

x1 = 0 ; y1 = 1000

x2 = 6 ; y2 = 4000

Slope = Rise / Run

Rise = y2 - y1 = 4000 - 1000 = 3000

Run = x2 - x1 = 6 - 0 = 6

Hence,

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Slope = 500

y - intercept = 1000 (from. Graph)

Equation in slope intercept form:

General form : y = mx + c

m = slope ; c = intercept

Equation is written as ;

y = 500x + 1000

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What is the coefficient in the expression 40a-61=17
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