Question

What is the equation of the line that passes through the points (-2, 1) and (-6, -5)?

Answer 1

Answer:

y=3/2x+4

Step-by-step explanation:

1.find the slope

y2-y1/x2-x1

-5-1/-6-(-2)

-5-1/-6+2

-6/-4

3/2

slope (m) is 3/2

2.y-y1=m(x-x1)

y-1=3/2(x-(-2))

y-1=3/2(x+2)

y-1=3/2x+6/2

y=3/2x+6/2+1

y=3/2x+8/2

y=3/2x+4