What is the equation of the line that passes through the points (-2, 1) and (-6, -5)?

Mathematics

1 answer:

Paha777 [63]3 years ago

4 0

Answer:

y=3/2x+4

Step-by-step explanation:

1.find the slope

y2-y1/x2-x1

-5-1/-6-(-2)

-5-1/-6+2

-6/-4

3/2

slope (m) is 3/2

2.y-y1=m(x-x1)

y-1=3/2(x-(-2))

y-1=3/2(x+2)

y-1=3/2x+6/2

y=3/2x+6/2+1

y=3/2x+8/2

y=3/2x+4

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sergiy2304 [10]

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