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AnnyKZ [126]
3 years ago
11

Someone please help 100 points

Mathematics
2 answers:
Rama09 [41]3 years ago
7 0

Answer:

Step-by-step explanation:

for first one, find the area multiplying 1in, 4in,4in, and 1in

for the second one find area with 5in, 3in, 3in and 5in

Hope this helps! Just find the area and you're golden!

4vir4ik [10]3 years ago
3 0

A.                      

Height=1+1=2in

Base=4+4=8in

Total 8+2=10in

B.

Height=3+3=6in

Base=5+5=10in

Total=10+6=16in

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The price of gold is often reported per ounce. At the end of 2005, this price was $513. At the end of 2015, it was $1060. By wha
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Answer:

106.63%.

Step-by-step explanation:  

We have been given that at the end of 2005, this price was $513. At the end of 2015, it was $1060.

To find the percentage of the price per ounce of gold increase we will use % increase formula.

\text{Percent Increase}=\frac{\text{Final value-Initial value}}{\text{Initial value}}\times 100

Let us substitute our given values in above formula.

\text{Percent Increase}=\frac{1060-513}{513}\times 100

\text{Percent Increase}=\frac{547}{513}\times 100

\text{Percent Increase}=1.0662768031189084\times 100

\text{Percent Increase}=106.62768031189084\approx 106.63

Therefore, the price of per ounce of gold increased by 106.63%.

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The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
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Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

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in 4/5 fraction of the game they scored two or more runs.

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