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If you write all the whole numbers from 1 to 500 in a row, what will be the 500th digit?

Hitman42 [59]

Answer:

Option A.

Step-by-step explanation:

We need to find the 500th digit if we write all the whole numbers from 1 to 500 in a row.

Single digit numbers are : 1-9 = 9 number = 9 digits

Double digit numbers are : 10-99 = 90 number = 180 digits

Total digits form 1 to 99 = 9+180 = 189

Now,

$500-189=311$

It means we have write 311 more digits.

After 99 we have 3 digit number.

311 is not divisible by 3. The number immediate before 311 which is divisible by 3 is 309.

$\frac{309}{2}=103$

It means the required digit is 2nd digit of 104th number after 99.

104th number after 99 is 203 and second digit of 203 is 0.

Therefore, the correct option is A.

3 0

3 years ago

HEEEEELP please i need it

Mrac [35]

Answer:

Person 3 earns the most money every year

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone explain how to do this

jolli1 [7]

Answer:

20%

Step-by-step explanation:

im not really good at percentages but from what i know you first make it a fraction by adding all the numbers together to get 55(denominator). then for the numerator you take the section that they want(11). 11/55 is equal to 20/100(divide 100 by 55 and multiply the quotient by 11 to get 20). 20/100 is 20%. hope this kinda helps.

7 0

2 years ago

The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.

ololo11 [35]

Answer: (a) {a, ar, ar², ar³, ar⁴, ar⁵...}, (b) arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

4 0

3 years ago

At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The num

horrorfan [7]

in the equation as we can say x= 2y-10.

so, substitute x=2y-10 everywhere then the x in 1240 gets cancelled with 2y-10 then solve the remaining you will get 4y-20+3y=1240

7y=1260

y=1260/7

y=180

then substitute the value of y everywhere

2x+3y=1240

2x+3(180)=1240

2x=1240-540

2x=700

x=350

DONE.

8 0

3 years ago