Help plz am desperate no links(will sue), no unhelpful answers (will report or sue), and plz have an explanation if you don't th
at's okay but brainliest for explanation. Thank y'all!
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Answer:
The probability that the weight of a randomly selected steer is between 920 and 1730 lbs
<em> P(920≤ x≤1730) = 0.7078 </em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given mean of the Population = 1100 lbs
Standard deviation of the Population = 300 lbs
Let 'X' be the random variable in Normal distribution
Let x₁ = 920
Let x₂ = 1730
<u><em>Step(ii)</em></u>
The probability that the weight of a randomly selected steer is between 920 and 1730 lbs
P(x₁≤ x≤x₂) = P(Z₁≤ Z≤ Z₂)
= P(-0.6 ≤Z≤2.1)
= P(Z≤2.1) - P(Z≤-0.6)
= 0.5 + A(2.1) - (0.5 - A(-0.6)
= A(2.1) +A(0.6) (∵A(-0.6) = A(0.6)
= 0.4821 + 0.2257
= 0.7078
<u><em>Conclusion:-</em></u>
The probability that the weight of a randomly selected steer is between 920 and 1730 lbs
<em> P(920≤ x≤1730) = 0.7078 </em>