Let the population of Elmore be "X".
Since that the population of Linton is 12 times as great as the population of Elmore, then it is considered to be "12x".
Since that the sum of both Elmore and Linton is 9.646, then "X + 12x = 9464" x+12x is 13x , so it should be "13x = 9464". Now, it is easy to find the population of Elmore which is 9464 / 13 = 742. Since that the population of Linton is 12 times the population of Elmore, then the population of Linton is "742 * 12 = 8904".
Answer:
![z = 15[\frac{\sqrt{3}}{2}]](https://tex.z-dn.net/?f=z%20%3D%2015%5B%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5D)
Step-by-step explanation:
To find the Z-side, we must take the cosine of the 30-degree angle of the main triangle
We know that the cosine of an angle is defined as:



Then:
![z = 15[\frac{\sqrt{3}}{2}}]](https://tex.z-dn.net/?f=z%20%3D%2015%5B%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%7D%5D)
Finalmente the side z is:
![z = 15[\frac{\sqrt{3}}{2}}]](https://tex.z-dn.net/?f=z%20%3D%2015%5B%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%7D%5D)
Answer:
3.2
Step-by-step explanation:
3.2t when t=1
replace t with 1 so 3.2(1)
hence =3.2
Answer:
18
Step-by-step explanation:
use this formula
A=(a+b
)/2 x h
****
A= (4+8)/2 x 3
A=(12)/2 x 3
A= 6 x 3
A= 18
The word can be represented as a set and in the roaster form the set of letters is {s, a, l, t}
<h3>What is set?</h3>
A set is a collection of clearly - defined unique items. The term "well-defined" applies to a property that makes it simple to establish whether an entity actually belongs to a set. The term 'unique' denotes that all the objects in a set must be different.
We have given letter:
"salt"
Here, no letter is repeated.
So we can write it as roaster form:
Let's denote the set as S
S = {s, a, l, t}
Number of element in the set = 4
We can make new set from it if the set has only vowels
S(v) = {a}
If set has only consonants:
S(c) = {a, l, t}
Thus, the word can be represented as a set and in the roaster form the set of letters is {s, a, l, t}
Learn more about the set here:
brainly.com/question/8053622
#SPJ1