Answer:
150.88
Step-by-step explanation:
just gotta fine the area for each square using the formula base times height with a good old calculator and add them all together, hopefully that's correct
Answer:
Increase the potential of charges in the circuit
Step-by-step explanation:
Hope this is correct
HAVE A GOOD DAY!
Answer:
0.36427
Step-by-step explanation:
Mean = λ = 18 messages per hour
P(X = x) = (e^-λ)(λ⁻ˣ)/x!
P(X ≤ x) = Σ (e^-λ)(λ⁻ˣ)/x! (Summation From 0 to x)
But the probability required is that the messages thay come in an hour is between 15 and 20, that is, P(15 < X < 20)
P(15 < X < 20) = P(X < 20) - P(X ≤ 15)
These probabilities will be evaluated using a cumulative frequency calculator.
P(X < 20) = 0.65092
P(X ≤ 15) = poissoncdf(18, 15) = 0.28665
P(15 < X < 20) = P(X < 20) - P(X ≤ 15) = 0.65092 - 0.28665 = 0.36427.
You can use the Poisson distribution calculator here
https://stattrek.com/online-calculator/poisson.aspx
Given: Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbon. Elena bought 6 pieces of ribbon.
To find: Who can buy which ribbon
Solution:
Ribbon Sizes
1 2/3 = 5/3 yard
4/5 yard
3 1/2 = 7/2 Yard
Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon
Yu bought 3 pieces of ribbon
=> 3 * 5/3 = 5
3 * 4/5 = 2.4
3 * 7/2 = 10.5
Nailah bought 5 pieces of ribbon
=> 5 * 5/3 = 8.33
5 * 4/5 = 4
5 * 7 /2 = 17.5
Elena bought 6 pieces of ribbon
=> 6 * 5/3 = 10
6 * 4/5 = 4.8
6 * 7 /2 = 21
Only value between 7 & 9 is 5 * 5/3 = 8.33
hence Nailah only can buy 1 2/3 = 5/3 yard ribbon
or there is some mistake in the data
< means “Less than” and the other one means “less than or equal to”
