Answer:

Step-by-step explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
Data given
Confidence =0.99 or 99%
represent the significance level
n =16 represent the sample size
We don't know the population deviation 
Solution for the problem
For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:

We know that
so then
and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:
"=T.INV(0.005;15)" and we got
on this case since the distribution is symmetric we know that the other critical value is 
Answer:
1,823.20
Step-by-step explanation:
I'm smart!
Answer:
it is 2.35
Step-by-step explanation:
Answer:
Between the lengths of 10 and 36 (exclusive).
Step-by-step explanation:
Since the lengths of any two sides is always greater than the third, the shortest possible length of the third side must be greater than 23 when added to 13. 23-13 = 10, so the third side must be greater than 10.
However, the third side also cannot exceed the length of the sum of the other two sides. 23+13 = 36, therefore the length must be less than 36.
The possible lengths of the third side lie between 10 and 36 (exclusive).
If we use 'l' for length, this range can be represented as follows:

Hope this helped!