Answer: b. Only statement (ii) is correct.
Step-by-step explanation:
The given five-number summary of the ages of passengers on a cruise ship is listed below.
Min 1
20 Median 29
38 Max 80
Inter-quartile range = 
- According to the 1.5(IQR) criterion for outliers : An data value is an outlier if it lies below
or above
.
Here , 

Since the minimum value>
( ∵ 1 > -7)
It means there is no value below
, so there is no low -outlier.
⇒ Statement (i) "here is at least one passenger whose age is a low outlier. " is false.
But the maximum value >
(∵ 85 > 65)
It means there are values above
.
⇒Statement (ii) "There is at least one passenger whose age is a high outlier" is true.
Hence, the correct answer is b. Only statement (ii) is correct.
5(5r-7)=-185
25r - 35 = - 185
25r = - 150
r = - 6