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3 years ago

12

PLEASE HELP I WILL GIVE BRAINLEST TO THE CORRECT ANSWER!

1 answer:

Yakvenalex [24]3 years ago

8 0

Explanation:

the work a force does is measured in newton-meters (N-m), which use the symbol of J. Time (t) is expressed in Second. Power (P) is expressed in Watt (W).

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A conducting sphere with radius R is charged until the magnitude of the electric field just outside its surface is E. The electr

dusya [7]

Answer:

he correct answer is V = ER

Explanation:

In this exercise they give us the electric field on the surface of the sphere and ask us about the electric potential, the two quantities are related

ΔV = ∫ E.ds

where E is the elective field and normal displacement vector.

Since E is radial in a spray the displacement vector is also radial, the dot product e reduces to the algebraic product.

ΔV = ∫ E ds

ΔV = E s

since s is in the direction of the radii its value on the surface of the spheres s = R

ΔV = E R

checking the correct answer is V = ER

8 0

4 years ago

A rock is thrown upward with a velocity of 18 meters per second from the top of a 38 meter high cliff, and it misses the cliff o

Roman55 [17]

The rock would be at a point 12 m from water at a time <u>4.8 s</u>.

Take the origin of the coordinate system at the top of the cliff. It is thrown upwards with a velocity u. When the rock is at a point 12 m from water, calculate the vertical displacement of the rock from the origin.

$y= -38m- (-12 m)=-26 m$

Use the equation of motion,

$y=ut +\frac{1}{2} at^2$

The rock falls under the acceleration due to gravity, directed down wards.

Substitute 18 m/s for u, -26 m for y and -9.8 m/s² for a=g.

$y=ut +\frac{1}{2} at^2\\ (-26 m)=(18m/s)t+\frac{1}{2}(-9.8m/s^2)t^2$

Solve the quadratic equation for t.

$t=\frac{(18m/s)(+/-)\sqrt{(18m/s)^2-4(4.9m/s^2)(-26m)} }{2(4.9m/s^2)}$

Taking only the positive value,

$t=\frac{(18 m/s)+(28.87 m/s)}{9.8 m/s^2)} \\ t=4.78 s$

After a time of <u>4.8 s</u> the rock would be at a distance of 12 m from water.

8 0

3 years ago

An electric fan is running on HIGH. After the LOW button is pressed, the angular speed of the fan decreases to 84.7 rad/s in 2.9

ale4655 [162]

The initial angular speed of the fan will be 55.0 rad/sec. The angular speed of the fan decreases to 84.7 rad/s in 2.96 s.

<h3>What is angular acceleration?</h3>

Angular acceleration is defined as the pace of change of angular velocity with reference to time.

Given data;

Final angular speed, $\rm \omega_f = 84.7 rad/s$

Initial angular speed, $\rm \omega_i = ?$

Time period,t= 2.96 s

Angular deceleration = 47.2 rad/s²

$\rm \alpha =\frac{\omega_f-\omega_i}{t} \\\\\rm 47.2 =\frac{84.7-\omega_i}{2.96} \\\\ \omega_i = 55.0 \ rad/sec$

Hence the initial angular speed of the fan will be 55.0 rad/sec.

To know more about angular acceleration refer to the link ;

brainly.com/question/408236

#SPJ

7 0

2 years ago

Ase answer will give brainliest

AnnZ [28]

2a. same

2b. less than

3. 250N, yes

7 0

3 years ago

A charged particle is launched with a velocity of 5.2 × 10^4 m/s at an angle of 35° with respect to a 0.0045-t magnetic field. i

svetlana [45]

Umm.... 19 because the force is changed

6 0

3 years ago