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vampirchik [111]
3 years ago
6

Three equal masses lie at the corners of an equilateral triangle of side l. find the center of mass.

Physics
1 answer:
hammer [34]3 years ago
6 0
<span>If two of the masses are at (0, 0) and (L, 0), by symmetry the x-coordinate of the third mass must be L/2, and then by the Pythagorean theorem its y-coordinate must be L(âš3)/2. Thus the position of the third mass is (L/2, L(âš3)/2). Let each mass be m and C be the position of its center of mass. Then C = (1/(3m)) (m(0, 0) + m(L, 0) + m(L/2, L(âš3)/2)). = (1/3) (3L/2, L(âš3)/2). = (L/2, L(âš3)/6). That is, X_c = L/2 and Y_c = L(âš3)/6.</span>
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