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3 years ago

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Collisions between atoms are often elastic, but sometimes inelastic collisions occur, and the lost kinetic energy can become int

ernal energy in the atoms, exciting electrons to higher energy orbitals or even ejecting then from the atom entirely, which is called ionization (and the required energy the ionization energy).2 (a) A Cs 133 atom (mass 133 amu) has an ionization energy of 4.0 eV.3 Express this energy in joules. (b) What is the minimum speed that a O16 atom can have if it is to ionize a cesium atom at rest upon impact?

1 answer:

Galina-37 [17]3 years ago

4 0

Answer:

a) E = 6.4 1019 J b) v = 0.69 10⁴4 m / s

Explication

a) convert E = 4.0 eV

1 eV = 1.6 10⁻¹⁹ J

E = 4.0 eV (1.6 10⁻¹⁹ J / 1 eV)

E = 6.4 10⁻¹⁹ J

b) Suppose we have a frontal shock and all the kinetic energy of oxygen is transferred to Cs

Ei = K = ½ m v²

Ef = 6.4 10⁻¹⁹ J

½ m v² = 6.4 10⁻¹⁹

The oxygen mass of the periodic table is

PA = 15,999 u

1u = 1.660 10⁻²⁷ kg

Pa = 15,999 1,660 10⁻²⁷ kg

m= Pa = 26,558 10⁻²⁷ kg

Let's calculate the speed

v2 = 2 / m 6.4 10⁻¹⁹

v2 = 2 / 26,558 10⁻²⁷ 6.4 10⁻¹⁹ =

v = √0.4819 10⁸

v = 0.69 10⁴4 m / s

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Which means:

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Read 2 more answers

Two lamps rated 60W; 240V and 100W, 240Vrespectively are connected in series to a 240V power source. Calculate;

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Answer:

See the answers below.

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Now we have a voltage source equal to 240 [V], so by means of the following equation we can find the current circulating in the circuit.

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So this is the answer for c) I = 0.67 [amp]

We know that the voltage of each lamp is 240 [V]. Therefore using ohm's law which is equal to the product of resistance by current we can find the voltage of each lamp.

a)

$V=I*R$

where:

V = voltage [V]

I = current [amp]

R = resistance [ohms]

Therefore we replace this equation in the first to have the current as a function of the resistance and not the voltage.

$P=V*I\\and\\V = I*R\\P = (I*R)*I\\P=I^{2}*R$

$60 = (0.67)^{2}*R\\R_{60}=133.66[ohm] \\and\\100=(0.67)^{2} *R\\R_{100}=100/(0.66^{2} )\\R_{100}=225 [ohm]$

b)

The effective resistance of a series circuit is equal to the sum of the resistors connected in series.

$R = 133.66 + 225\\R = 358.67 [ohms]$

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