Question

The length of a rectangular room is 2 feet longer than three times the width of the room perimeter is 132 feet what's the room dimensions

Answer 1

Answer:

width=16feet

length=50feet

Step-by-step explanation:

let width be x and length be 3x+2

perimeter=2(length+width)

132=2(3x+2+x)

132=6x+4+2x

132=8x+4

132-4=8x

128/8=8x/8

16=x

width=16feet

length=16×3+2

length=50feet

Answer 2

Answer:

The length is 50 feet and the width is 16 feet

Step-by-step explanation:

Let w represent the width of the room.

If the length is 2 feet longer than 3 times the width, the length can be represented by 3w + 2.

Use the perimeter formula, p = 2l + 2w. Plug in the perimeter and plug in 3w + 2 as l, the length:

p = 2l + 2w

132 = 2(3w + 2) + 2w

Simplify and solve for w:

132 = 6w + 4 + 2w

132 = 8w + 4

128 = 8w

16 = w

So, the width is 16 feet.

Plug in 16 as w into 3w + 2 to solve for the length:

3w + 2

3(16) + 2

48 + 2

= 50

The length is 50 feet and the width is 16 feet