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eimsori [14]
2 years ago
8

The probability of a golden retriever catching a tennis ball in mid-air is 74%. Find the probability that a golden retriever cat

ches three tennis balls in mid-air.
Mathematics
1 answer:
professor190 [17]2 years ago
4 0

Answer:

Step-by-step explanation:

Given a large enough sample size the probability is 100%

If the question is "What is the probability of catching 3 tennis balls in three tosses in mid air. Sample size is 3

0.74³ = 0.405224 or about 41%

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WILL MARK YOU BRAINLIEST
Shalnov [3]

Answer:

the answer is 3/2

Step-by-step explanation:

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4 0
3 years ago
Edward is collecting data on the average length of lizards from head to tail for a particular generation. Initially, the average
Zina [86]

Answer:

The general form of a natural logarithmic function is <em>f(x)=a In(x-h) +k.</em> Since the initial average length of the lizards was 20 centimeters, one possible point (h+1,k) through which the function passes is (0,20).

In this case, h= -1 since h +1 = 0 and k = 20.

It follows that x - h = (-1) = x + 1.

So, the function takes the form <em>f(x) = a In(x + 1) +20. </em>

The average length of the lizards after 2 years is 22.197. So f(2) =22.197. We substitute this value into the function

Step-by-step explanation:

<em>f(2) = a In(2 +1) +20 </em>

<em>22.197 = a In(3) + 20 </em>

<em></em>\frac{2.197}{1.099}<em>≈ a </em>

<em>2 ≈ a</em>

So the function that represents the average length of the lizards across this generation is <em>f(x) = 2 In(x+1) +20 </em>

3 0
3 years ago
Use technology or a z-score table to answer the question.
Alik [6]

Answer:

The second choice: Approximately 65.2\% of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each z entry has two decimal places.

Let \mu represent the mean of a normal distribution of variable X. Let \sigma be the standard deviation of the distribution. The z-score for the observation x would be:

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question,

  • \mu = 240.
  • \sigma = 9.3.

Calculate the z-score for x_1 = 225 and x_2 = 245. Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}.

\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}.

The question is asking for the probability P(225 \le X \le 245) (where X is between two values.) In this case, that's the same as P(-1.61 \le Z \le 0.54).

Keep in mind that the probabilities on many z-table correspond to probability of P(Z \le z) (where Z is no greater than one value.) Therefore, apply the identity P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1) to rewrite P(-1.61 \le Z \le 0.54) as the difference between two probabilities:

P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61).

Look up the z-table for P(Z \le 0.54) and P(Z \le -1.61):

  • P(Z \le 0.54)\approx 0.70540.
  • P(Z \le -1.61) \approx 0.05370.

\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}.

3 0
3 years ago
3x-2y=-1 and 3x-2y=9 solve using elimination
luda_lava [24]
You can put them vertically
then subtract them
but if you do it, it will be 0=-10 that doesn't make sense. 
So the answer is that there is no answer!
3 0
3 years ago
What factors of 72 add to 17
Naddik [55]
72 = 8*9
8 + 9 = 17

The factors you're looking for are 8 and 9.
7 0
3 years ago
Read 2 more answers
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