Can you help with this question?

Name of the period that has the digit 913

enyata [817]

It would be 9.13 since u would have to make it a decimal

6 0

3 years ago

Tickets to a movie cost $7.25 for adults and $5.50 for students. a group of friends purchased 8 tickets for $52.75. how many adu

frez [133]

There will be 5 adults and 3 students

5 0

2 years ago

I need help on number 16

ollegr [7]

There will be two squares.

Think about it: The shorter side is 3.5 feet. The longer side is 7 feet. If he cuts it in half on the longer side, he's taking the length of that longer side, and dividing it by 2. 7/2=3.5.

So, you'd have two squares, both with a length and width of 3.5 feet.

5 0

2 years ago

A grocery store buys items and then applies a markup of 70%. What is the retail price of item that originally costs $10?

S_A_V [24]

Answer:

$17.00

Step-by-step explanation:

10 x 1.70 = $17.00

8 0

2 years ago

Read 2 more answers

The mayor of a town has proposed a plan for the construction of an adjoining bridge. A political study took a sample of 1700 vot

lara [203]

Answer:

$z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562$

$p_v =P(z>2.562)=0.0052$

So the p value obtained was a very low value and using the significance level given $\alpha=0.02$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

Step-by-step explanation:

Data given and notation

n=1700 represent the random sample taken

$\hat p=0.66$ estimated proportion of voters that favored construction

$p_o=0.63$ is the value that we want to test

$\alpha=0.02$ represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that percentage of residents who favor construction is more than 63%.:

Null hypothesis: $p \leq 0.63$

Alternative hypothesis: $p > 0.63$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.66 -0.63}{\sqrt{\frac{0.63(1-0.63)}{1700}}}=2.562$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.02$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.562)=0.0052$

So the p value obtained was a very low value and using the significance level given $\alpha=0.02$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that at 2% of significance the proportion of voters that favored construction is higher than 0.63 or 63%.

7 0

2 years ago