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sergeinik [125]
3 years ago
7

Please help for answer 56/125-177/625=

Mathematics
1 answer:
hram777 [196]3 years ago
8 0
56/125-177/625= 280/625 - 177/625 = ( 280 - 177 ) / 625 = 103 / 625 = 0.1648
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28,18,8,-2 is this arithmetic ?
Tresset [83]

Answer:

yes it is arithmetic because:

28 - 10= 18

18 - 10= 8

8 - 10= -2

it keeps decreasing by the same number (10). Therefore, it is arithmetic.

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3 years ago
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3 years ago
Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
Read 2 more answers
Aubrey is making cone-shaped hats for a birthday party. She mistakenly thinks that she will need about 104 square inches of pape
Mashutka [201]

Answer:

Option C. is the correct option.

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Aubrey is making cone-shaped hats for a birthday party. She mistakenly thinks that she will need about 104 square inches of paper for each hat.

Cone with diameter six inches and slant height eight inches.

What is the correct amount of paper Aubrey will need per hat? Explain Aubrey’s mistake. Use 3.14 for π and round to the nearest inch.

A.  About 70 in2; Aubrey found the surface area of the cone, but did not include the base.

B.  About 70 in2; Aubrey used the diameter instead of the radius to find the surface area of a cone.

C.  About 75 in2; Aubrey found the surface area of the cone and included the base.

D.  About 75 in2; Aubrey found the volume of the cone instead of the surface area.

Lateral surface area of a cone = Paper required to for each hat

Lateral surface area = πrl

Here r = radius of the cone

l = lateral height of the cone

Lateral surface area = π(3)(8)

                                 = 75.36 square inches

                                 ≈ 75 square inches

Therefore, total paper required for each cap is about 75 square inches.

Total surface area of the cone (Lateral area + Area of the base)

= πr(r + l)

= 3.14(3)(3 + 8)

= 103.62

≈ 104 square inches.

Aubrey did a mistake by finding the total surface area (including base area) of the cone instead of lateral surface area.

Therefore, option C. is the correct option.

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3 years ago
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