Question

3. A car starts from rest and accelerates uniformly over a time of 6.21 seconds

Answer 1

We have,

t = 6.21 s

s = 111 m

u = 0 m/s

To determine: "a" of the particle.

We know,

s = ut + ½ at²

⇒ s = ½ at²

⇒ a = 2s/t²

⇒ a = [2(111 m)]/(6.21 s)²

⇒ a = (222 m)/(38.5641 s²)

⇒ a ≈ 5.75 m/s²