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Luba_88 [7]
2 years ago
15

Pleaseeee hurryyy i needd helppp

Mathematics
1 answer:
Nady [450]2 years ago
3 0

Answer:

C. There is one solution, because the coefficients of the variables on both sides of the equation are different.

Step-by-step explanation:

The solution is m = 1

~theLocoCoco

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Find the measures of EAF DAE and CAD
sdas [7]
You have to build an equation to find the answer,

angles in a straight line add upto 180° 
so your equation would be,

12x+30°=180°
      -30    -30
=12x=150°
   ÷12  ÷12
=x=12.5°

now find the measures of the angles by using 12.5 as x.

angle EAF= 2x
                 =2×12.5
                 =25° degrees

angle DAE= 4x
                 =4×12.5
                 =50°degrees

angle CAD=6x
                 =6×12.5
                 =75°degrees

check,
30+25+50+75=180°degrees

hope this helps.......
7 0
3 years ago
A regular hexagonal prism has a height of 12 cm and base edge length of 10 cm. Identify its lateral area and surface area rounde
kolbaska11 [484]
To find the l.a., you multiply the perimeter of the base (the hexagon) by the height. 
l.a. = 60 x 12

surface area is harder :(
you have to find the apothem and all that jazz. sorry i can't help more, good luck!

3 0
3 years ago
A boy bought an article for £9. He spent £4
Marina86 [1]

Answer:

Profit % = 39%

Step-by-step explanation:

Cost price of the article = 9

Price for repairing = 4

Therefore, Total cost of the article = 9 + 4 = 13

Selling price  of the article = 18

Profit = 18 - 13 = 5

Hence,

          Profit \% = \frac{Profit}{Cost \ price} \times 100\\\\

                        = \frac{5}{13} \times 100\\\\=38.46 \%\\\\=38.5 \%

Profit percent (to the nearest %) = 39%

4 0
3 years ago
Triangle KJL is inscribed in semicircle O shown below such that JK=6 and JL=11. Which of the following is closest to the radius
lakkis [162]

Uhh, answer choices?

In any case, since \triangle KJL is inscribed in a semicircle, it is a right triangle (due to the inscribed angle theorem). Thus, by the Pythagorean theorem, KL=\sqrt{6^2+11^2}=\sqrt{157}. Now, the circumradius of a right triangle (the radius of the circle passing through all three of its vertices) is simply half its hypotenuse, so OJ=OK=OL=\frac{\sqrt{157}}{2}\approx \boxed{6.265}.

7 0
2 years ago
A family pays $19 each month for Internet access. Next month, the cost will increase by 5% because of an equlpment fee. After th
Elena L [17]

Answer:yk i’m looking for the answer too, i can’t find it

Step-by-step explanation:

7 0
3 years ago
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