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3 years ago

9

ΔABC with vertices A(-3, 0), B(-2, 3), C(-1, 1) is rotated 180° clockwise about the origin. It is then reflected across the line

y = -x. What are the coordinates of the vertices of the image?

1 answer:

Savatey [412]3 years ago

8 0

Triangle APQ is the image of ABC under a dilation centered at vertex A with scale factor ½. Triangle RBT is the image of ABC under a dilation centered at vertex B with scale factor ¾ . Which statement about ABC , APQ , and RBT is correct? none of the triangle are similar

All three triangles are similar

Triangle APQ an RBT are not similar

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Solve using elimination. 4. 2x + 3y = 12 2x – y = 4 5. 5x – 2y = - 19 2x + 3y = 0

ANTONII [103]

I am attaching a document showing the steps.

3 0

2 years ago

A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe

djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

$\mathbf{h(t) = -16t^2 + 160t}$

Differentiate the function with respect to t

$\mathbf{h'(t) = -32t + 160}$

Set to 0

$\mathbf{h'(t) = -32t + 160 = 0}$

So, we have:

$\mathbf{-32t + 160 = 0}$

Collect like terms

$\mathbf{-32t =- 160 + 0}$

$\mathbf{-32t =- 160}$

Solve for t

$\mathbf{t = \frac{- 160}{-32}}$

$\mathbf{t = 5}$

Hence, the projectile reaches the maximum after 5 seconds

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8 0

2 years ago

Giving brainliest! Please show the working out

tiny-mole [99]

Answer:

see explanation

Step-by-step explanation:

(a)

OC = OB ( both radii of the circle )

Thus Δ BOC is isosceles with congruent base angles.

∠ BOC = ∠ BCO = 50°

(b)

∠ ACB = 90° ( angle in a semicircle ), then

∠ ACO = 90° - 50° = 40°

OA = OC ( both radii of the circle )

Thus Δ ACO is isosceles with congruent base angles.

∠ BAC = ∠ ACO = 40°

7 0

3 years ago

mr Goodwill [35]

Answer:

The coordinates of E are $E(x,y) = \left(\frac{9}{2}, 0 \right)$ .

Step-by-step explanation:

The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.

Vectorially speaking, dilation is defined by the following operation:

$P'(x,y) = O(x,y) + k\cdot [P(x,y) - O(x,y)]$ (1)

Where:

$O(x,y)$ - Point of reference.

$P(x,y)$ - Original point.

$P'(x,y)$ - Dilated point.

$k$ - Dilation factor.

By applying this operation, point B becomes point D:

$B(x,y) = (0,4)$ , $D(x,y) = (0,6)$

$D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]$

$D(x,y) = (0,0) + k\cdot (0,4)$

$(0,6) = (0,0) +(0,4\cdot k)$

$(0, 6) = (0,4\cdot k)$

$k = \frac{3}{2}$

Lastly, we transform point C into point E by applying the same operation: $C(x,y) = (3, 0)$ , $O(x,y) = (0,0)$ and $k = \frac{3}{2}$

$E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]$

$E(x,y) = \left(\frac{9}{2}, 0 \right)$

The coordinates of E are $E(x,y) = \left(\frac{9}{2}, 0 \right)$ .

8 0

3 years ago

Please help what does B equal and C equal

ycow [4]

Answer:

C=47

B=133

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers