- About 127.3(square root of 16,200, or 90√2) Look at this problem like a right triangle. Each leg is 90 feet, so the hypotenuse is the square root of 90^2 + 90^2
- About 52.3(square root of 2735.64) Another right triangle problem! Once again, with Pythagorean theorem (a^2 + b^2 = c^2) You can deduce that 60^2 = 29.4^2 + the width of the TV^2.
- About 11.6(Square root of 134.75)Another right triangle problem, you can deduce that 9.5^2 + The pool length^2 = 15^2
Hope it helps <3
(If it does, please give brainliest, only need one more for rank up :) )
Answer: point F is at <u> 0.6 </u> on the number line
=============================================================
Explanation:
The ratio 2:3 scales up to 2x:3x for some positive real number x.
This means the distance from D to F is 2x units, and the distance from F to E is 3x units. Combine those two smaller distances to get 2x+3x = 5x to represent the full distance from D to E.
D is at -3 and E is at 6. This is a distance of 9 units since |-3-6| = |-9| = 9
Set this equal to the 5x from earlier and solve
5x = 9
x = 9/5
x = 1.8
This leads to 2x = 2*1.8 = 3.6
Therefore, we'll move 3.6 units from -3 to -3+3.6 = 0.6 which is the location of point F on the number line.
Notice that from 0.6 to 6 is 5.4 units and that 3x = 3*1.8 = 5.4 matches up to help confirm the answer.
Answer :Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.
Step-by-step explanation:
Considering the quadrilateral with vertices
d(0,0)
i(5,5)
n(8,4)
g(7,1)
Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.
From the figure a, it is clear that the quadrilateral has
Two pairs of sides
Each pair having two equal-length sides which are adjacent
The angles being equal where the two pairs meet
Diagonals as shown in dashed lines cross at right angles, and one of the diagonals does bisect the other - cuts equally in half
Please check the attached figure a.
Answer:
m∠1=80°
m∠2=112°
m∠3=131°
m∠4=80°
m∠5=37°
Step-by-step explanation:
First you have to find m∠2
To do that find m∠6 (I created this angle shown in pic below)
Find m∠6 by using the sum of all ∠'s in a Δ theorem
m∠6=180°-(63°+49°)
m∠6=68°
Now you can find m∠2 with the supplementary ∠'s theorem
m∠2=180°-68°
m∠2=112°
Then you find m∠5 using the sum of all ∠'s in a Δ theorem
m∠5=180°-(112°+31°)
m∠5=37°
Now you can find m∠1
m∠1=180°-(63°+37°)
m∠1=180°-100°=80°
m∠4 can easily be found too now:
m∠4=180°-(63°+37°)
m∠4=80°
m∠3=180°-49°
m∠3=131°
Distance between -4 and -3 is 1 and there is no distance between 0
