Answer:
The rider's speed will be approximately 35 m/s
Explanation:
Initially the rider has kinetic and potential energy, and after going down the hill, some of the potencial energy turns into kinetic energy. So using the conservation of energy, we have that:

The kinetic and potencial energy are given by:


So we have that:






So the rider's speed will be approximately 35 m/s
Answer:
Charge = 4.9096 x 10⁻⁷ C
Explanation:
First, we find the resistance of the copper wire.
R = ρL/A
where,
R = resistance = ?
ρ = resistivity of copper = 1.69 x 10⁻⁸ Ω.m
L = Length of wire = 2.16 cm = 0.0216 m
A = Cross-sectional area of wire = πr² = π(0.00233 m)² = 1.7 x 10⁻⁵ m²
Therefore,
R = (1.69 x 10⁻⁸ Ω.m)(0.0216 m)/(1.7 x 10⁻⁵ m²)
R = 2.14 x 10⁻⁵ Ω
Now, we find the current from Ohm's Law:
V =IR
I = V/R
I = 3.27 x 10⁻⁹ V/2.14 x 10⁻⁵ Ω
I = 1.52 x 10⁻⁴ A
Now, for the charge:
I = Charge/Time
Charge = (I)(Time)
Charge = (1.52 x 10⁻⁴ A)(3.23 x 10⁻³ s)
<u>Charge = 4.9096 x 10⁻⁷ C</u>