Question

A solid conducting sphere of radius 2.00 cm has a charge of 8.95 µC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge of −2.33 µC. Find the electric field at the following radii from the center of this charge configuration.

Answer 1

Answer:

1.23 × 10⁷ N/C

Explanation:

Given that:

The radius of the solid sphere R₁ = 2.00 cm

The charge q₁ = 8.95 × 10⁻⁶ C

The radius of the inner spherical shell R₂ = 4.00 cm

The radius of the outer spherical shell R₂ = 5.00 cm

The charge q₂ = -2.33 × 10⁻⁶ C

Assuming the radius of the configuration = 7 cm

Then, the net charge of the system is

$Q_{net} = q_1 +q_2$

$Q_{net} =$ 8.95 + (-2.33)

$Q_{net} =$ 6.62  µC

Thus, the electric field for the system can be calculated by using the formula;

$E = k \dfrac{Q_{net}}{R^2}$

$E = \dfrac{(9\times 10^9) \times (6.62 \times 10^{-6})}{(7\times 10^{-2})^2}$

$E = 12159183.67 \ N/C$

E = 1.23 × 10⁷ N/C