Answer:
$161.34
Step-by-step explanation:
Answer:
3.5
Step-by-step explanation:
First we use the concept of relative speed.
The rates of the 2 planes are 625 mph & 575 mph.
Relative speed will be:
(speed of plane A)+(speed of plane B)
=625+575
=1,200 mph
Distance=4200 miles
Thus the time taken for them to meet will be:
Time=distance/speed
=4200/1200
=3.5 hours
We therefore conclude that the planes met after 3.5 hours.
Hope this helps!
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.
Answer:
what are the answer chooice bc i cant see the picture
Step-by-step explanation:
