Complete question is;
A cash register contains coins. 10 pennies, 11 nickels, 13 dimes, and 6 quarters. A cashier will randomly choose two coins one at a time without replacement. What is the probability that the cashier will choose a penny first, followed by a dime?
Answer:
1/12
Step-by-step explanation:
We are told there are 10 pennies, 11 nickels, 13 dimes, and 6 quarters.
Thus total number of coins = 10 + 11 + 13 + 6 = 40 coins
Probability of picking a penny first is;
10/40 = 1/4
After which we will have 39 coins left.
Probability of a dime after that will be 13/39 = 1/3
Thus,probability of picking a penny first then a dime will be; ¼ × ⅓ = 1/12
