Answer:
![\huge\boxed{\sf 3000x}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csf%203000x%7D)
Step-by-step explanation:
Sum is Addition
![\sf 1000x + 2000 x \\\\x ( 1000 + 2000) \\\\x ( 3000) \\\\3000 x](https://tex.z-dn.net/?f=%5Csf%201000x%20%2B%202000%20x%20%5C%5C%5C%5Cx%20%28%201000%20%2B%202000%29%20%5C%5C%5C%5Cx%20%28%203000%29%20%5C%5C%5C%5C3000%20x)
Answer:
5x-1 < 2x+11
<=> 5x - 2x < 11 +1
<=> 3x < 12
<=> x < 4
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
-4/2 = -2
-2 + 5 = 3
Answer:
28
Step-by-step explanation:
The initial number n must be a multiple of 4 (otherwise n/4 will not be an integer) and must be bigger than 0. Therefore if the initial number is less than 28 then it should be a number in the next list: 4, 8, 12, 16, 20 and 24, but from those options just 12 could give a second stop but not a third stop.
so the smallest number that allow three stops is 28 since:
Therefore 28 could not only stop three times but infinite times.
Answer:
see explanation
Step-by-step explanation:
Consider the values of y
, 2, 10, 50
Consider the ratio between consecutive terms
2 ÷
= 5
10 ÷ 2 = 5
50 ÷ 10 = 5
Since the ratio is common then the terms form a geometric sequence
The n th term of a geometric sequence is
= a![(r)^{n-1}](https://tex.z-dn.net/?f=%28r%29%5E%7Bn-1%7D)
where a is the first term and r is the common ratio, hence
= ![\frac{2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D)
← explicit formula