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3 years ago

What is the equation of a line that is perpendicular to y=4x-5 and passes through (-4,6)

Mathematics

1 answer:

lozanna [386]3 years ago

4 0

Answer:

y=-1/4x+5

Step-by-step explanation:

perpendicular lines have slopes that multiply to -1.

Our given line:

y=4x-5

the slope (m) in it is 4. To find the slope of the perpendicular line:

4m=-1

divide by 4

m=-1/4

the slope of the new line is -1/4

here's our equation so far:

y=-1/4x+b

Since the line will pass through the point (-4,6) we can use it to solve for b (y intercept)

so substitute (-4,6) into the equation

6=-1/4(-4)+b

6=1+b

5=b

the y intercept is 5

so our equation is:

y=-1/4x+5

hope this helps! :D

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