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atroni [7]
3 years ago
6

What is the equation of a line that is perpendicular to y=4x-5 and passes through (-4,6)

Mathematics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

y=-1/4x+5

Step-by-step explanation:

perpendicular lines have slopes that multiply to -1.

Our given line:

y=4x-5

the slope (m) in it is 4. To find the slope of the perpendicular line:

4m=-1

divide by 4

m=-1/4

the slope of the new line is -1/4

here's our equation so far:

y=-1/4x+b

Since the line will pass through the point (-4,6) we can use it to solve for b (y intercept)

so substitute (-4,6) into the equation

6=-1/4(-4)+b

6=1+b

5=b

the y intercept is 5

so our equation is:

y=-1/4x+5

hope this helps! :D

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jeka94

Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
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3 years ago
Let x be normally distributed with mean μ = 133 and standard deviation σ = 23. use table 1.
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If f(x) is the total cost, in dollars, of x candles, which of the following statements best describes the meaning of f(2)=6
nevsk [136]

Answer: A) The total cost of 2 candies is $6.00.

Step-by-step explanation:

Hi, the question is incomplete,  options are :

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