Question

Answer + explanation would be appreciated

Answer 1

Answer:

-2 + 2i

Step-by-step explanation:

$(1 + i)^{3}$

i = $\sqrt{-1}$

$(1 + \sqrt{-1})^3$

$[(1 + \sqrt{-1})(1 + \sqrt{-1})] (1 + \sqrt{-1})$

distribute the first 2 expressions

(1 + 2$\sqrt{-1}$ - 1 ) $(1 + \sqrt{-1})$

distribute

1 + 2$\sqrt{-1}$ - 1 +

combine like terms

-2 + 2 $\sqrt{-1}$

which is -2 + 2i