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Bezzdna [24]
3 years ago
9

A traveler is walking on a moving walkway in an airport. The traveler must walk back on the walkway to get a bag he forgot. The

traveler's ground speed is 1 fts against the walkway and 5 ft/s with the walkway. What is the traveler's speed off the walkway? What is the speed of the moving walkway? The traveler's speed off the walkway is ft/s.​
Mathematics
1 answer:
zaharov [31]3 years ago
5 0

Answer: here is your answer

Step-by-step explanation:

You can put this solution on YOUR website!

+t+ = traveler's speed in ft/sec

+w+ = walkway's speed in ft/sec

given:

+t+-+w+=+2+

+t+%2B+w+=+6+

-------------

Add the equations

+2t+=+8+

+t+=+4+

and

+t+%2B+w+=+6+

+4+%2B+w+=+6+

+w+=+2+

The traveler's speed off the walkway is 4 ft/sec

The speed of the moving walkway is 2 ft/sec

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19.55\pm2.145

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We use the equation \bar x\pm z^*\sigma/\sqrt n, where \bar x=19.55, \sigma=6.33, n=41, and z^*=2.17. We obtain z^* from the z-score of a 0.97 confidence level.

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Felicity's dog eats two cups of dog food per day. Felicity's dog eats at least one-quarter cup more than one-half of the amount
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Answer:

2 > \frac{1}{2} m + \frac{1}{4}  

Step-by-step explanation:

Given:

  • Felicity's dog eats two cups of dog food per day :2

If the amount of food that Martin's dog eats is represented by using m

Felicity's dog eats at least one-quarter cup more than one-half of the amount Martin's dog eats: \frac{1}{2} m + \frac{1}{4}

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2 > \frac{1}{2} m + \frac{1}{4}  

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Which inequality is represented by the graph? y≥35x−1.5 y≤35x−1.5 y<35x−1.5 y>35x−1.5
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Answer:

y > 0.6x - 1.5

Step-by-step Explanation:

We need two points, to get to the equation of the graph.

Since we've got the following equation for two points (x1, y1), (x2, y2):-

\boxed{ \mathsf{ \red{y - y_{1} =  \frac{y_{2} - y_{1}}{x_{2} - x_{1}} (x - x_{1})  }}}

okay soo

I found two points that lie on this graph, not on the shaded region but yeah the dotted line which defines the graph.

one point is <u>(0, -1.5)</u> which lies on the y axis(the point where the dotted line touches the y axis)

other point is <u>(2.5, 0)</u> and this lies on the x axis

placing these points in the place of (x1, y1) and (x2, y2) in the above mentioned equation

\mathsf{\implies y - ( - 1.5) =  \frac{0 -( - 1.5)}{2.5 -0 } (x -0 )}

you can take any one as (x1, y1) or (x2, y2).

so upon solving the above equation we get

\mathsf{\implies (y  +  1.5) =  \frac{0  +  1.5}{2.5  } (x  )}

\mathsf{\implies y  +  1.5 =  \frac{ 1.5}{2.5  } x  }

\mathsf{\implies y  +  1.5 =  \frac{ \cancel{1.5}\:\:{}^3}{\cancel{2.5}\:\:{}^5 } x  }

\mathsf{\implies y  +  1.5 =  \frac{ 3}{5 } x  }

multiplying both sides by 5

\mathsf{5y + 7.5 = 3x}

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now we'll find the inequality

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replacing x and y with 0

\mathsf{\implies5(0) + 7.5 = 3(0)}

\mathsf{\implies0 + 7.5 = 0}

this is absurd, 7.5 is not equal to 0 so we're gonna replace that equals sign with that of inequality

7.5 is greater than 0! so,

\mathsf{\implies7.5 > 0}

this goes for the whole equation, since we didnt swap any thing from left to right side of the equation or vice versa we can use this sign, to obtain the required inequality

\mathsf{5y + 7.5 > 3x}

dividing this inequality by 5, since there's no co-efficient in front of y in the given answers

we get

y + 1.5 > 0.6x

taking 1.5 to the RHS

<h3>y > 0.6x - 1.5 </h3>

that is the last option

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