Answer:
option: A
Step-by-step explanation:
" if for a polynomial with rational coefficients has irrational roots then these irrational roots will always appear in pair " .
we are given that 
and 
are two roots of a polynomial equation with rational coefficients, then it's complex conjugate is also a root of this polynomial equation i.e. ' 
' and ' 
' are also roots of this polynomial equation.
Hence, option A is correct.
Answer:
see step-by-step below
Step-by-step explanation:
1) y - 2 > 3
Add 2 to both sides: y > 5
2) y ≤ 2
Draw a closed circle at y = 2 then shade the numbers to the left
3) y ≥ 250
where y = savings
4) The image isn't very clear, so I can't tell if it's a closed or open circle on -4.
If it is closed, it will be y ≤ -4
If it is open, it will be y < -4
5) -4 < f
Draw an open circle at f = -4 then shade the numbers to the right
6) x < -3.5
Draw an open circle at x = -3.5 then shade the numbers to the left
7) closed circle ... shade to the left of 8 ... make y equal to or less than 8.
8) F ≤ 6
C - closed circle at 6 with shaded numbers to the left
9) y > 2.75
Betty saved more than $2.75 every month
10) 1 + x < 5
Subtract 1 from both sides: x < 4
11) x ≥ -2.5
12) 1 ≤ m means that m is equal to or greater than 1
solutions: 4, 1, 2.3
Answer:none of the above
Step-by-step explanation:
Interesting factoid: Only perfect squares have an odd number of factors. So we know to try 4, 9, and 16, and ignore the rest. It's 16, whose factors are 1, 2, 4, 8, and. 16 .
