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Vinil7 [7]
3 years ago
7

Write an absolute value equation to satisfy the given solution set shown on a number line.

Mathematics
2 answers:
Lynna [10]3 years ago
6 0
/1/2/ sorry I don’t know how to do the straight line
Nezavi [6.7K]3 years ago
5 0
The answer would be
|1/2|
if you need it in a different form comment and lmk
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Peter and Angad win some money and share it in the ratio 1:4. Peter gets £11. How much did Angad get?
Arada [10]

Answer:

i believe the answer is 44

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3 years ago
Which number produces irrational number when added to 0.5
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Square root of 3 and Pi
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4 years ago
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Create the f(x) function based on the table. Your answer should be in function notation. X f(x) - 10 -6 -9 -5 1-8 -4 -7 1-3 5 9​
Minchanka [31]

Answer:

f(x) = x + 4

Step-by-step explanation:

First create an equation in slope-intercept form, y = mx + b. To do this, find the rate of change or slope (m), and the y-intercept (b).

Using two pairs, (-7, -3) and (-8, -4),

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-4 -(-3)}{-8 -(-7)} = \frac{-1}{-1} = 1

m = 1

To find b, substitute m = 1, x = -7 and y = -3 into y = mx + b.

Thus:

-3 = (1)(-7) + b

-3 = -7 + b

-3 + 7 = b

4 = b

b = 4.

Replace y with f(x), m with 1 and b with 4 in y = mx + b.

The function would be:

f(x) = x + 4

6 0
3 years ago
C(n)=-6+5(n-1)<br> find the 8th term in this sequence
Goryan [66]

Answer:

29

Just replace n by 8 ===> C(8) = -6+5(8-1) = - 6 + 5x7 = -6+35 = 29

Step-by-step explanation:

We have been given a sequence formula. We are asked to find the 8th term of our given sequence.

We know that an arithmetic sequence is in form A_n=a_1+(n-1)d, where,

A_n=\text{ nth term of sequence},

A_1=\text{ 1st term of sequence},

n = Number of terms in sequence,

d = Common difference.

To find the 8th term of our given sequence, we will substitute n=8 in our given formula.

c(n)=-6+5(n-1)

c(8)=-6+5(8-1)

c(8)=-6+5(7)

c(8)=-6+35

5 0
3 years ago
Show that only one n, n+2 and n+4 are divisible by 3
babymother [125]
N+2 divide 3 so it should be correct hope it helped
3 0
3 years ago
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