Answer:
-x^4y^2 +7x^3y^3 +2x^2y^4 -3xy^5
Step-by-step explanation:
The powers of x in the terms of the given expression are ...
4, 3, 1, 2
so, we want to swap the last two terms to put them in the desired order:
-x^4y^2 +7x^3y^3 +2x^2y^4 -3xy^5
F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)