Question

Can someone please help me do this

Answer 1

Answer:

Step-by-step explanation:

CD is Pole

∠CAD = 4°  {Alternate interior angles}

ΔCAD,

$\dfrac{opposite \ side}{adjacent \ side}= tan 4\\\\ \dfrac{90}{AD}=tan \ 4\\\\ \dfrac{90}{AD} = 0.069\\\\90 = 0.069*AD\\\\ \dfrac{90}{0.069}=AD\\\\AD = 1304 \ ft$

In ΔCDB,

∠B = 5° {Alternate interior angles}

$Tan \ 5 = \dfrac{90}{BD}\\\\0.09* BD = 90\\\\BD = \dfrac{90}{0.09}\\\\BD = 1000 \ ft$