What number multiplied by itself 2 times equals 1/100

a coach asked two players how much water they drank before practice. Ashley said she drank 1/2 pint and Claire said she drank 0.

Andre45 [30]

1. The problem gives the following information: Ashley said she drank 1/2 pints and Claire said she drank 0.7 pints.

2. Therefore, to solve this problem you must follow the proccedure that is shown below:

3. You must sum the amount of water that Ashley and Claire drank before the practice. Then, you have:

1/2 pints=0.5 pints (Ashley)
0.7 pints (Claire)

x=0.5 pints+0.7 pints
x=1.2 pints

How many pints of water did Ashley and Claire drink combined?

The answer is: 1.2 pints or 1 1/5 pints

8 0

3 years ago

Y = |x| translated one unit to the left

Assoli18 [71]

Answer:

It is moved one unit to the right.

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

La temperatura a una distancia r del centro de una lámina está dada por T=40 (r2?2r) . La variación instantánea de la temperatur

PilotLPTM [1.2K]

For this, the first thing to do is to assume that the function of temperature with respect to r is written in one of the following ways:

Way 1:

$T = 40 (r ^ 2 + 2r)$

Way 2:

$T = 40 (r ^ 2-2r)$

To find the instant variation we must find the derivative of the temperature with respect to the distance r.

We have then:

For function 1:

$\frac {dT} {dr} = 40 \frac {d ((r ^ 2 + 2r))} {dr}\\$

$\frac {dT} {dr} = 40 (2r + 2)$

Rewriting

$\frac {dT} {dr} = 80r + 80$

For function 2:

$\frac {dT} {dr} = 40 \frac {d ((r ^ 2-2r))} {dr}$

$\frac {dT} {dr} = 40 (2r-2)$

Rewriting

$\frac {dT} {dr} = 80r-80$

Answer:

The instantaneous variation of the temperature with respect to r is given by:

Assuming function 1:

$\frac {dT} {dr} = 80r + 80$

Assuming Function 2:

$\frac {dT} {dr} = 80r-80$

6 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST!

Naily [24]

Answer:

The answer is given in the picture

Please mark me brainliest

7 0

3 years ago

You are getting a line-up ready for a school kickball game. you have 77 girls and 77 boys. the rules state each child must kick

mezya [45]

1. Since each child kicks the same number of times, it is not important whether he or she kicks 1 time, 2, 3 or more times. So let all of them kick 1 time.

2. assume we start with a girl. We can start with either of the 77 girls, then second is a boy which can be either of the 76, the third is a girl which can be either of the 76 remaining, then the forth is one of the 76 boys...

3. So starting with a girl we have

77*(77)*76*(76)*75*(75)....*2*(2)*1*(1)=77!*77!

4. OR we could have started with a boy, where we would get again 77!*77!

5. Answer: 77!*77!+77!*77!=2 $(77!)^{2}$

3 0

4 years ago