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IRISSAK [1]
3 years ago
12

Find the pair of numbers whose sum is 46 and whose product is a maximum.

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0
To solve this problem you must apply the proccedure shown below:

 1. Let's call:

 x the first number and and the other number 46-x

 2. Then, the product of both numbers is:

 y=x(46-x)

 3. When you apply the distributive property, you obtain:

 y=46x-x^2

 4. As you can see, the coefficient of x^2 is negative, this means that the maximun value is at the vertex of the parabola.

 5. Then, you have:

 h=-b/2a
 h=-46/2(-1)
 h=23   (x coordinate)

 6.Then:

  y=46x-x^2
 y=46(23)-(23)^2
 y=529

 Therefore the answer is: 23 and 529.

 
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Rudiy27

The elevation of the plane is 3600 ft

Let

  • h = elevation of plane,
  • d = distance from Marsha's house to spot on ground below plane = 3600 feet and
  • Ф = angle of elevation of plane = 45°

From the triangle, we have the trigonometric ratio

tanФ = h/D

<h3>Elevation of the plane</h3>

Making h subject of the formula, we have

h = DtanФ

substituting the values of the variables into the equation, we have

h = DtanФ

h = 3600 ft × tan45°

h = 3600 ft × 1

h = 3600 ft

So, the elevation of the plane is 3600 ft

Learn more about elevation of the plane here:

brainly.com/question/26380084

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2 years ago
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zloy xaker [14]

Answer:

see explanation

Step-by-step explanation:

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A = 0.5 × perimeter × apothem

Here side length = 3.25, hence perimeter = 10 × 3.25 = 32.5 m, thus

A = 0.5 × 32.5 × 5 = 81.25 m²

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Answer:

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Step-by-step explanation:

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The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
Anettt [7]

Answer:

1) The size of the colony after 4 ​days is 6553 mosquitoes

2) After t = 4.9\ days

Step-by-step explanation:

To answer this question you must use the growth formula

N = N_0e ^ {kt}

Where

N_0 is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and N_0=1000 then N = 1600

Then we use these values to find k.

1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47

Now that we know k we can find the size of the colony after 4 days.

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To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

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6 0
3 years ago
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The range of the function is all numbers less than it equal to 0

Step-by-step explanation:

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3 years ago
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