Question

Helllllllllllllllllllllllllllp please

Answer 1

Answer:

0° and 18°

Step-by-step explanation:

3tan²β - tanβ = 0

tanβ(3tanβ - 1) = 0

tan β = 0 ⇒ $\beta _{1}$ = 0°

3tan β - 1 = 0 ⇒ tan β = $\frac{1}{3}$ ⇒ $\beta _{2}$ = arctan ( $\frac{1}{3}$ ) ≈ 18°

Answer 2

Answer:

$3 \tan {}^{2} \theta - \tan\theta= 0 \\ \tan\theta(3 \tan \theta- 1) = 0✓\\\\\tan\theta = 0 \\\boxed{\theta = 0°} ✓\\\\ 3 \tan\theta - 1 = 0 \\3 \tan \theta = 1 \\ \tan \theta = \frac{1}{3} \\ \theta = { \tan }^{ - 1} ( \frac{1}{3} ) \\\boxed{\theta = 18.4°}✓$

★ Value of the ∅ is 0° and 18.4°.