This
can be solved using Dalton's Law of Partial pressures. This law states that the
total pressure exerted by a gas mixture is equal to the sum of the partial
pressure of each gas in the mixture as if it exist alone in a container. In
order to solve, we need the partial pressures of the gases given. Calculations
are as follows:<span>
<span>P = 3.00 atm + 1.80 atm + 0.29 atm + 0.18 atm + 0.10 atm</span></span>
<span><span>P = 5.37 atm</span></span>
H2SO.Mgslfurmobile phase in this experiment
Answer:
Explanation:
91.4
grams
Explanation:
C
=
m
o
l
v
o
l
u
m
e
2.45
M
=
m
o
l
0.5
L
2.45
M
⋅
0.5
L
=
m
o
l
m
o
l
=
1.225
Convert no. of moles to grams using the atomic mass of K + Cl
1.225
m
o
l
⋅
(
39.1
+
35.5
)
g
m
o
l
1.225
m
o
l
⋅
74.6
g
m
o
l
=
1.225
⋅
74.6
g
=
91.4
g
The limiting reagent is <u>H₂SO₄</u>
<u><em>calculation</em></u>
<u><em> </em></u>Step 1 :write the equation for reaction
2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O
Step 2: use the mole ratio to determine the moles of product produced from each reactant
that is from equation above,
NaOH : Na₂SO₄ is 2 :1 therefore the moles of Na₂So₄
= 10.0 moles x 1/2 = 5.0 moles
H₂SO₄ :Na₂SO₄ is 1:1 therefore the moles of Na₂SO₄ is also = 3.50 moles
H₂SO₄ is the limiting reagent since it produces less amount of Na₂SO₄
Answer:
3.011×1023 individual carbon dioxide molecules
