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3 years ago

Calculate the solubility (in g/L) of CaSO4(s) in 0.500 M Na2SO4(aq) at 25°C . The sp of CaSO4 is 4.93×10^−5 .

Chemistry

1 answer:

jeka943 years ago

7 0

When you calculate the first two numbers in 493×10

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The car wit fastest acceleration is the tempest. it has an acceleration of 6.1 m/s. suppose the car accelerates from rest to a f

ziro4ka [17]

<u>Given:</u>

Initial velocity (v1) = 0 m/s

Final velocity (v2) = 30 m/s

Acceleration (a) = 6.1 m/s2

<u>To determine:</u>

The time (t) taken to reach the final speed

<u>Explanation:</u>

Use the relation:

Acceleration (a) = [final velocity(v2) - initial velocity (v1)]/time (t)

t = (v2-v1)/a = 30-0/6.1 = 4.92 s

Ans: Time taken is around 4.9 s

3 0

3 years ago

Suppose you wanted to dissolve 40.0 g NaOH in enough H2O to make 6.00 dm3 of solution

dezoksy [38]

Molarity of solution = 1.6 M

<h3>Further explanation</h3>

Given

40 g NaOH

6 L solution

Required

Steps to solve the problem of molarity

Solution

No additional information about the question.

If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)

But if you want to know the molarity of a solution, then

1. we calculate the moles of NaOH

$\tt mol=\dfrac{mass}{MW}$

MW(molecular weight) of NaOH=

Ar Na+ Ar O + Ar H

23 + 16 + 1 = 40 g/mol

so mol NaOH :

$\tt mol=\dfrac{40~g}{40~g/mol}=1~mol$

2. Molarity(M)

$\tt M=\dfrac{n}{V}\\\\M=\dfrac{1}{6}\\\\M=0.16$

5 0

3 years ago

What is the technique for calculating the age of remains from the amount of C-14 that is left in once alive living things?

Marizza181 [45]

Carbon 14 dating? is that one of your choices

5 0

3 years ago

Read 2 more answers

Property is part of a system that does not depend on the size or the amount is called....

Reil [10]

The answer is A.extensive.

3 0

2 years ago

c. The reaction Br2 (l) --> Br2 (g) has ΔH = 30.91 kJ/mol and ΔS = 93.3 J/mol·K. Use this information to show (within close a

egoroff_w [7]

Answer:

The answer to your question is given below.

Explanation:

From the question given above, the following data were obtained:

Br₂ (l) —> Br₂(g)

Enthalpy change (ΔH) = 30.91 KJ/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:

1 KJ/mol = 1000 J/mol

Therefore,

30.91 KJ/mol = 30.91 × 1000

30.91 KJ/mol = 30910 J/mol

Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.

Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:

Enthalpy change (ΔH) = 30910 J/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

ΔS = ΔH / T

93.3 = 30910 / T

Cross multiply

93.3 × T = 30910

Divide both side by 93.3

T = 30910 / 93.3

T = 331.29 K

Thus, the boiling temperature of bromine is 331.29 K

6 0

3 years ago