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3 years ago

Calculate the solubility (in g/L) of CaSO4(s) in 0.500 M Na2SO4(aq) at 25°C . The sp of CaSO4 is 4.93×10^−5 .

Chemistry

1 answer:

jeka943 years ago

7 0

When you calculate the first two numbers in 493×10

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Write the quantities 3 x 10^-4 cm and 3 x 10^4 km in ordinary notation

Goshia [24]

To write quantities in ordinary notation, you need to notice the power of the exponent.
If the power is positive, then you move the decimal point to the right by the number the power in exponent tells you.
If the power is negative, then you move the decimal point to the left by the number the power in exponent tells you.

We have:
3 x 10^-4 : the power of exponent is negative, therefore, we will move the decimal point 4 places to the left.
3 x 10^-4 = 0.0003 km

3 x 10^4 : he power of exponent is positive, therefore, we will move the decimal point 4 places to the right.
3 x 10^4 = 30000 km

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4 years ago

20. In which medium do sound waves move the fastest?

Nataliya [291]

Answer:

D. Solids

Explanation:

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3 years ago

Read 2 more answers

The steps in every scientific investigation must_______________________.

Marizza181 [45]

Answer:

B. begin with a hypothesis

Explanation:

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3 years ago

Technetium-99 is an ideal radioisotope for scanning organs because it has a half-life of 6.0 h and is a pure gamma emitter. supp

Nadusha1986 [10]

Answer: 20 mg Te-99 remains after 12 hours.

Explanation: N(t) = N(0)*(1/2)^(t/t1/2)

N(t) = (80 mg)*(0.5)^(12/6)

N(t) = 20 mg remains after 12 hours

3 0

3 years ago

How many grams are in 1.946 moles of nacl

Ilia_Sergeevich [38]

Answer:

113.8g

Explanation:

Statement of problem: mass of 1.946mole of NaCl

Given parameters:

Number of moles of NaCl = 1.946mole

Unknown: mass of NaCl

Solution

To find the mass of NaCl, we apply the concept of moles which expresses the relationship between number of moles and mass according to the equation below:

Number of moles = $\frac{mass}{molar mass}$

To find the molar mass of NaCl:

the atomic mass of Na = 23g

atomic mass of Cl = 35.5g

Molar mass of NaCl = (23 + 35.5) = 58.5gmol⁻¹

Mass of NaCl = Number of moles x molar mass of NaCl

Mass of NaCl = 1.946 x 58.5 = 113.8g

7 0

3 years ago