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alexira [117]
3 years ago
7

Calculate the solubility (in g/L) of CaSO4(s) in 0.500 M Na2SO4(aq) at 25°C . The sp of CaSO4 is 4.93×10^−5 .

Chemistry
1 answer:
jeka943 years ago
7 0
When you calculate the first two numbers in 493×10
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Write the Ka expression for an aqueous solution of hydrofluoric acid: (Note that either the numerator or denominator may contain
damaskus [11]

Answer:

Ka = ( [H₃O⁺] . [F⁻] ) / [HF]

Explanation:

HF is a weak acid which in water, keeps this equilibrium

HF (aq)  +  H₂O (l)  ⇄  H₃O⁺ (aq)  +  F⁻ (aq)      Ka

2H₂O (l)  ⇄  H₃O⁺ (l)  +  OH⁻ (aq)   Kw

HF is the weak acid

F⁻ is the conjugate stron base

Let's make the expression for K

K = ( [H₃O⁺] . [F⁻] ) / [HF] . [H₂O]

K . [H₂O] = ( [H₃O⁺] . [F⁻] ) / [HF]

K . [H₂O] = Ka

Ka, the acid dissociation constant, includes Kwater.

4 0
3 years ago
In which row has Aaron made an error in his chart?
hammer [34]

Answer:Row 2

Explanation:

7 0
3 years ago
To create an ion you simply need to add or take away an electron true or false
BigorU [14]

Answer:

True

Explanation:

ion: an atom or molecule with a net electric charge due to the loss or gain of one or more electrons.

5 0
3 years ago
Read 2 more answers
The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.085 M, how long would it take u
olasank [31]

Answer: It will take 8.2 minutes until the concentration decreases to 0.055 M

Explanation:

The time after which 99.9% reactions gets completed is 40 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{13min}=0.053min^{-1}

b)  Time taken for 0.085 M to decrease to 0.055 M

t=\frac{2.303}{0.053}\log\frac{0.085}{0.055}

t=8.2min

Thus it will take 8.2 minutes until the concentration decreases to 0.055 M

5 0
3 years ago
A gas has a volume of 5.0 L at a pressure of 50 kPa. What happens to the volume when temperature is held constant and the pressu
Leto [7]

2.0L        is the answer for sure

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