The identity of the noble gas is the sample is Krypton
<h3>Ideal Gas law</h3>
From the question, we are to determine the identity of the noble gas in the sample
From the ideal gas equation, we have that
PV = nRT
∴ n = PV / RT
Where P is the pressure
V is the volume
n is the number of moles
R is the gas constant
and T is the temperature
From the given information,
P = 678 mmHg = 0.892105 atm
V = 363 mL = 0.363 L
R = 0.08206 L.atm/mol.K
T = 35 °C = 35 + 273.15 K = 308.15 K
Putting the parameters into the equation, we get
n = (0.892105 × 0.363)/ (0.08206 × 308.15)
n = 0.0128 moles
Now, we will determine the Atomic mass of the sample
Using the formula,
Atomic = Mass / Number of moles
Atomic mass of the substance = 1.07 / 0.0128
Atomic mass of the substance = 83.6 amu
The noble gas with the closest atomic mass to this value is Krypton.
Molar mass of Krypton = 83.798 amu
Hence, the identity of the noble gas is the sample is Krypton
Learn more on Ideal Gas law here: brainly.com/question/20212888
#SPJ12
