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3 years ago

MAINTAINING SKILLS

Mathematics

1 answer:

masya89 [10]3 years ago

5 0

Answer:

1. $30

2. $47.50

3. $7.20

Step-by-step explanation:

1. ( 30 + 45 + 15 ) / 3 = 30

2. ( 18 + 93 + 34 + 45 ) / 4 = 47.50

3. ( 9 + 4 + 5 + 8 + 10 ) = 7.20

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Find the sum of the smallest 7- digit number and largest 4-digit number

Snowcat [4.5K]

1009999

Hope it helps you...

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3 years ago

Mike bought 5 new baseball trading cards to add to his collection . the next day hos dog ate half of his collection. there are n

Sav [38]

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4 years ago

For (triangle)DEF, you are required to construct the median DG to EF. Which of the following must be performed first?

iren2701 [21]

Answer: C. Bisect DE at G.

Step-by-step explanation:

In a triangle, a median is a line segment drawn from a vertex to the midpoint of the opposite side of the vertex.

So, for triangle DEF , if we draw the median DG to the opposite side EF.

Here EF is the opposite side to vertex D.

So, G must be the midpoint of line segment EF.

So , we need to first mark G on EF.

i.e. we need to bisect EF at G.

So first step would be : Bisect EF at G.

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3 years ago

Determine whether each point lies on the graph of the equation.(a) 2x - y - 3 = 0 (a) (1, 2)Yes, the point is on the graph.No, t

Neko [114]

Answer:

a) (1, 2) not on the graph.

b) (1, -1) is on the graph.

Step-by-step explanation:

Given the equation of the line as:

$2x - y - 3 = 0$

The points given are

a) (1, 2)

To determine whether it is on the graph of the line or not.

To do so, we can do 2 things:

1. Draw the graph and plot the point on the graph to check whether it is on the graph or not.

2. To put the point in the given equation of the line, whether the equation is satisfied or not.

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put $x=1, y=2$ in the Left Hand Side (LHS) of equation.

$2\times 1 - 2 - 3\\\Rightarrow -3 \neq 0 , RHS$

(1, 2) Not on the graph.

(b) (1, -1)

For method 1: Kindly refer to the attached image of the line and point plotted.

Method 2:

Let us put $x=1, y=-1$ in the Left Hand Side (LHS) of equation.

$2\times 1 - (-1) - 3\\\Rightarrow 3-3 = 0 = RHS$

(1, -1) is on the graph.

3 0

4 years ago

How do i check an equation for extraneous solutions?

Marina86 [1]

Example:

$\sqrt x(x+1)=0$

This suggests two solutions, $x=0$ and $x=-1$ .

However, upon plugging these solutions back into the equation, you get

$\sqrt0(0+1)=0(1)=0$

which checks out, but

$\sqrt{-1}(1-1)=0$

does not because $\sqrt x$ is defined only for $x\ge0$ (assuming you're looking for real solutions only). So, we call $x=-1$ an extraneous solution, and the complete solution set (over the real numbers) is $x=0$ .

7 0

3 years ago

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