<span>So
I only have ones, tens and hundreds block. I need to find a way how can I fit
the given number 1 718.
=> Since I have hundreds block, I can divide 1 718 by 100
=> 1 718 / 100, how many 100s are there in 1 718
=> 17 hundreds
=> now we only have 18 left
=> 18 / 10, how many 10s are there in 18
=> 1 tens
=> Now we only have 8 left
=> 8 / 1, how many ones are there in 8
=> 8
=> 17 hundreds, 1 tens, and 8 ones.</span><span>
</span>
<span>So Steward scored 5 for the first round, that will be our constant.
There is 3 more rounds for him to score at least 30.
at least tells us this is a greater than or equal to 5+3p<30</span>
7x+5y is the answer
yepyep
For this case, the area is given by:
A = x * (200-2x)
Rewriting:
A = 200x-2x ^ 2
Deriving the expression we have:
A '= 200-4x
Equaling zero we have:
200-4x = 0
We clear x:
4x = 200
x = 200/4
x = 50 feet
Then, the maximum area is:
A (50) = 50 * (200-2 * 50)
A (50) = 5000 feet ^ 2
Answer:
the maximum possible area that can be enclosed with his 200ft of fencing is:
A (50) = 5000 feet ^ 2
