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m_a_m_a [10]
2 years ago
11

Whats 32% of 80???????????

Mathematics
2 answers:
Debora [2.8K]2 years ago
8 0

Answer: 25.6

Step-by-step explanation:

Masteriza [31]2 years ago
3 0
It is definitely 25.6
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Help will give brainliest
Anarel [89]

Answer:

Quadrant 2

Step-by-step explanation:

The answer is quadrant two because the answer is in the form of -x,y. When the x is negative and the y is positive, it is always going to be in quadrant 2. As you can see in the image below, quadrant 1 is going to be all positive, quadrant two is going to be negative then positive, quadrant three is going to be all negative, and quadrant 4 is going to be positive then negative. Use this as a guide for the rest of your question. I hope this helps!

8 0
3 years ago
Please help -2x++8-6=-32
arlik [135]

Answer:

x = 17

Step-by-step explanation:

-2x+8-6=-32

lets isolate the x variable:

-2x=-32-8+6

-2x = -34

x= -34/-2

x= 34/2

x= 17

3 0
3 years ago
The American Water Works Association reports that the per capita water use in a single-family home is 63 gallons per day. Legacy
Debora [2.8K]

Answer:

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

df=n-1=28-1=27  

p_v =P(t_{(27)}  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=60 represent the sample mean

s=8.9 represent the sample standard deviation

n=28 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 63, the system of hypothesis would be:  

Null hypothesis:\mu \geq 63  

Alternative hypothesis:\mu < 63  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=28-1=27  

Since is a one side lower test the p value would be:  

p_v =P(t_{(27)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.  

5 0
3 years ago
How would you find the volume of this cone?
posledela

Area of cone = 1/3 base × height = 1/3 × 8 × 10 = approximately 26.7 m

Ans= approx. 26.4 m

Happy to help. Please mark as brainliest!

4 0
3 years ago
7/35 reducing to the simplest form
nata0808 [166]

Step-by-step explanation:

\frac{7}{35}  =  \frac{7}{7 \times 5}  =  \frac{1}{5}  \\

4 0
3 years ago
Read 2 more answers
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