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MissTica
4 years ago
9

What is the domain and range of : y=(1/3)^x

Mathematics
1 answer:
loris [4]4 years ago
6 0
X can be any number, so the domain is all real numbers (-∞, +∞)
y is always larger than 0 in this case, so the range is all real numbers larger than 0 (0, +∞)
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Three out of four student surveyed in a school said they will vote for nuncio for class president. Predict how many of the 340 s
elena55 [62]
3/4 is .75. translate that to percentages, and you get 75%. This means that it is likely that 75% of the 340 students in total will vote for Nuncio. 
write it out:
.75*340
solve:
255

about 255 students are likely to vote for Nuncio
5 0
4 years ago
Read 2 more answers
Select the example which illustrates the distributive property of 7 × 39
Lemur [1.5K]

Answer:

d) 7(30 + 9) = 7(30) + 7(9)

Step-by-step explanation:

<u>Distributive method</u>:

  • a(b + c) = ab + ac

<u>Here given</u>:

  • 7 × 39

Among the option's:

<u>1st option</u> (7 + 3) (7 + 9) is wrong, changes <u>final answer</u>.

<u>2nd option</u> (7 × 30) + 9 is wrong, changes <u>final answer</u>.

3rd option 39 × 7 shows commutative property of multiplication.

<u>4th option</u> show distributive method.

3 0
1 year ago
Read 2 more answers
I really need help finding the solution!!
Mrac [35]

Answer:

-0.5 is not a solution

2 is a solution

Step-by-step explanation:

To check if something is a solution of the equation, you need to substitute the value in place of the variable

15 + 2y = -12 - 4y

15 + 2(-0.5) = -12 - 4(-0.5)

15 - 1 = -12 + 2

14 ≠ -10 ∴ -0.5 is not a solution

5 - 2(3x + 5) = 3 - 10x

5 - 2[3(2) + 5] = 3 - 10(2)

5 - 2(6 + 5) = 3 - 10(2)

5 - 12 - 10 = 3 - 120

-17 = -17 ∴ 2 is a solution

3 0
3 years ago
Can anyone help me with this?
vova2212 [387]

h = -4.9t^2 + vt

In our problem,

v = 12

t = 2

Let's plug our numbers into the equation.

h = -4.9(2)^2 + (12)(2)

h = -19.6 + 24

h = 4.4 m

4 0
3 years ago
Solve the rational equation 1/n-4 - 2/n = 3/4-n
Leokris [45]

Answer:

n=4

Step-by-step explanation:

Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:

\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]

=> \[(8-n)*(4-n) =n*(n-4)*3\]

=> \[n-8 =3n\]

=> \[2n =8\]

=> n = 4

5 0
3 years ago
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