Using the dimensions of a new scale drawing created using a scale factor of 0.15, find the dimensions of the original rectangle.

Help me solve this please it’s for my homework due tonight!!

natulia [17]

Answer:

h = 8

Step-by-step explanation:

Area of rectangle: base * height

So, by substituting the values given, we can write this equation:

Note: 1/4 = 0.25, so 3 1/4 = 3.25

A = b * h

26 = 3.25 * h

Divide both sides by 3.25.

h = 8

I hope this helps! Feel free to ask any questions!

3 0

2 years ago

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

2 years ago

Kaitlynn needs 3 pounds of fruit for a salad,

Greeley [361]

Answer:

2 of the 1/3 Bananas and 5 of the 1/4 strawberries

Step-by-step explanation:

two of the 1/3 bananas can complete the pound of grapes and one of the 1/4 of strawberries can complete the pound of apples so then u got 4 more of 1/4 and u got three pounds exact

5 0

2 years ago

What is the answer? I am so lost- thanks for any help given.

aev [14]

Answer:

i think that the answer is 13 meters

Step-by-step explanation:

7 0

2 years ago

Evaluate ∫ e3x cosh 2x dx A.1/ e5x+1/ex+C 10 2 B. 1/ e3x + 1/ x + C 42 C. 1/ e5x + 1/ 10 5 x + C D. 1/ e5x + 1/ ex + C 22

Irina18 [472]

Sh(2x) = (e^2x + e^-2x)/2

Thus the integral becomes 

Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] 

= e^5x/10 + e^x/2 + C
=(1/10)(e^5x) + (1/2)(e^x) + C

3 0

2 years ago