All categories

3 years ago

Find all x-values for which f ( x ) = 2 for the function below.

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

8 0

Answer:

Step-by-step explanation:

First let us get the equation of the coordinates

y-y0 = m(x-x0)

Using the coordinates ( - 3, 2 ), ( - 1, 0 )

m = 0-2/-1-(-3)

m = -2/2

m = -1

Substitute m = -1 and (-1, 0) into the formula

y - 0 = -1(x+1)

y = -x-1

f(x) = -x-1

Since f(x) = 2

2 = -x-1

-x = 2+1

-x = 3

x = -3

Hence the value of x is -3

You might be interested in

Use the distributive property to complete the following statement 4(x-1)=4x-___

Flura [38]

Answer:

A. 4

Step-by-step explanation:

4*x-4*1=4x-4

5 0

3 years ago

1.8.3 practice - functions<br><br>11. Find f(2) and f(a+h) when f(x) = 3x^2 + 2x + 4.

drek231 [11]

The answer is f(2) = 20

3 0

2 years ago

1. ARCHAEOLOGY While digging a hole to plant a tree,

klio [65]

2(pi)r

2(pi)0.75
Circumference is 4.71.

7 0

3 years ago

Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf

erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

$(\overline{x}_1-\overline{x}_2)\pm t^*\times SE$ ,

where $(\overline{x}_1-\overline{x}_2)$ = sample mean difference .

$t^*$ = critical t value (two-tailed)

SE= Standard error.

Given : $(\overline{x}_1-\overline{x}_2)=23$

$t^*=2.262$

SE= 4.2

Now, the confidence interval for mean difference will be :-

$23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)$

Hence, the required confidence interval : (13.4996, 32.5004)

8 0

3 years ago

For what value of c does the following system have no solution?<br><br> 1/2x+1/5y=2<br> 5x+2y=c

Minchanka [31]

Answer:

Step-by-step explanation:

$\frac{1}{2}x+\frac{1}{5}y = 2 \mid 5x + 2y = c$

First let's multiply the 1st equation by 10.

$5x + 2y = 20 \mid 5x + 2y = c$

So, we can see that the equations have the same coefficients and that implies they are equal.

So the equation has no solutions for. $c \in R \setminus{20}$

3 0

3 years ago

Read 2 more answers