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tatyana61 [14]
2 years ago
9

Mrs. Lovejoy makes flower arrangements. She has 36 red carnations, 60 white carnations, and 72 pink carnations. Each arrangement

must have the same number of each color. What is the greatest number of arrangements she can make if she uses every carnation?
Mathematics
1 answer:
Marat540 [252]2 years ago
8 0

Answer:

12 arrangements

Step-by-step explanation:

We solve this question using the Greatest Common Factor method.

We are told that:

She has 36 red carnations, 60 white carnations, and 72 pink carnations.

The same number of each item should be in each basket.

The greatest number of baskets is calculated as follows:

Step 1

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

The factors of 72 are: 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

Step 2

We Identify the number that is greatest and common amongst 36,60, and 72

This is 12.

Then the greatest common factor is 12

Therefore, the greatest number of arrangements she can make if she uses every carnation is 12 arrangements

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Step-by-step explanation:

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Step-by-step explanation:

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\bf \begin{cases} x=3\implies &x-3=0\\ x=1+3i\implies &x-1-3i=0\\ x=1-3i\implies &x-1+3i=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-3)(x-1-3i)(x-1+3i)=0 \\\\\\ (x-3)\underset{\textit{difference of squares}}{([x-1]-3i)([x-1]+3i)}=0\implies (x-3)([x-1]^2-[3i]^2)=0 \\\\\\ (x-3)([x^2-2x+1]-[3^2i^2])=0\implies (x-3)([x^2-2x+1]-[9(-1)])=0

[ correction added, Thanks to @stef68 ]

\bf (x-3)([x^2-2x+1]+9)=0\implies (x-3)(x^2-2x+10)=0 \\\\\\ x^3-2x^2+10x-3x^2+6x-30=0\implies x^3-5x^2+16x-30=f(x) \\\\\\ \stackrel{\textit{applying a translation with a -2f(x)}}{-2(x^3-5x^2+16x-30)=f(x)}\implies -2x^3+10x^2-32x+60=f(x)

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