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Maurinko [17]
3 years ago
9

A 32-ft pipe must be cut into three pieces. The longest piece will be twice as long as the shortest piece, and the medium-sized

piece will be 4 feet longer than the shortest piece. Find the length of each piece of pipe.
Mathematics
1 answer:
True [87]3 years ago
8 0

Answer:

7, 11, 14 feet from shortest to longest

Step-by-step explanation:

Let's say that the shortest pipe is equal to x, and work from there.

The medium size piece is 4 feet longer than the shortest piece, so it is equal to 4+x

The longest piece is twice as long as the shortest piece, so it is equal to 2 * x.

The three pieces added up make up the 32 feet pipe, so we can write this as

(2*x) + (4+x) + x = 32

2*x + 4 + x + x = 32

4 * x + 4 = 32

subtract 4 from both sides to isolate the x and its coefficient

4 * x = 28

divide both sides by 4 to isolate the x

x= 7

Therefore, the shortest piece is x=7 feet long. The medium piece is x+4=11 feet long, and the longest piece is x*2=14 feet long

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there are 60 teams attend a chess tournament. every team will play with every other team exactly once. Supposed each team has a
Karolina [17]

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

The reason for arriving at the above probability is as follows:

The given parameters are;

The number of teams in the tournament, n = 60

The chance of a team winning a game = 50% = 0.5

The number of ties = No ties

The required parameter:

The probability that no two teams win the same number of games

Method:

Calculate the number of ways no two teams win the same number of games, and divide the result by the total number of possible outcomes

Solution:

The number of matches played, n = \dbinom {60} {2} = 1,770

The possible outcomes = 2; Winning or losing

The total number of possible outcomes, n_p = 2¹⁷⁷⁰

The number of games won by each team is between 0 and 59

The ways in which no two teams won the same number of games is given by the games won by the teams to be 0, 1, 2,..., 57, 58, 59

Therefore, the number of ways no two teams won the same number of games, the required outcomes, n_k = 59!

Probability = \dfrac{Number \ of \ possible \ outcomes}{Number \ of \ required\ outcomes}

The probability that no two teams win the same number of games is given as follows;

\mathbf{P(No \ two \ teams \ won \ the \ same \ number \ of \ games)} = \dfrac{n_k}{n_p}

Therefore;

P(No \ two \ teams \ won \ the \ same \ number \ of \ games) = \dfrac{59!}{2^{1,770}} \approx \mathbf{2.084 \times 10^{-453}}

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

Learn more about probability theory here:

brainly.com/question/1539712

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