-6m+13=0 (put all like terms together)
-6m=-13 (subtracted 13 from both sides to leave m alone)
m=2.17 (divided both sides by -6)
Solution:
The table which is about kind of jeans and it's color is
Style Color
regular light blue
loose fit indigo
boot cut washed
slim fit black
slim fit blue
(a) A regular can be chosen out of five colors, A loose fit can also be chosen in five colors,Similarly a boot cut as well as slim fit can also be chosen out of five colors.
If you consider this as a relation , total number of relation that is total jeans = 1×5 + 1×5 +1×5+1×5= 20 Jeans = 10 Pairs of jeans(Possible)
(b) Total number of jeans , if i have one pair of jeans of each possible style and color = As there are 5 colors and 4 styles , the jeans are in pair = 5×4×2=40
Number of Black color jeans = 2× black color in 4 styles= 2×4=8
Probability of an event = 
Probability of choosing a pair of black jeans at random=
A: no solution!
first, simplify each side of the equation.
3x + 5 - 10x simplifies to -7x + 5.
8 - 7x - 12 simplifies to -7x - 4.
then, add +7x on both sides of the equation to get the variable alone. if you add 7x to each side, you get left with 0.
so, that leaves 5 = -4 which is not true. so, that means there is no solution.
Answer:
The correct answer is certain with probability equal to 1.
Step-by-step explanation:
Probability is a mathematical framework which helps us to analyze chance of the outcome in a particular experiment. The value of probability is given by the ratio of the possible outcomes favorable to a certain experiment to the total outcomes.
We say an event is certain when the probability is 1 and the probability is zero when the event is uncertain.
Here the experiment is picking a blue card from a bag containing all blue cards.
Possible outcomes are all the cards colored blue in the bag.
Total outcomes are also all the blue cards in the bag.
∴ The value of probability is 1 as the event is certain because if we pick a card from the bag containing only blue cards, it would certainly give us a blue card.